🏦IBPS PO Reasoning Ability44 questions

Inequality Questions for IBPS PO Reasoning Ability

Inequality questions give relationships between variables (direct symbols or letter codes) and ask which conclusions are certainly true, testing precise handling of >, ≥ and = chains. Parikshala's question bank has 44 exam-pattern Inequality questions for IBPS PO, each with a step-by-step solution (11 easy, 25 medium, 8 hard). Reasoning Ability carries 40 of 100 marks in IBPS PO Prelims.

What Inequality Questions Test

  • Direct inequality chains (A > B ≥ C)
  • Coded inequalities (symbols standing for >, <, =)
  • Certain vs possible conclusions
  • Either-or cases on complementary conclusions

Question bank coverage by sub-pattern

Direct Inequality · 16Coded Inequality · 10Quantity Comparison Based Inequality · 5Advanced Inequality Patterns · 3Equality in Chain · 2 · 2

How Inequality Appears in IBPS PO

35
Reasoning Ability questions in Prelims
40
marks for the section (of 100 total)
60 min
Prelims duration
0.25
negative marks per wrong answer

Inequality is part of the Reasoning Ability section (20% of the IBPS PO syllabus). See the full IBPS PO Prelims breakdown.

Inequality Solved Examples for IBPS PO

12 exam-pattern inequality questions from the practice bank, each with a full solution.

1Easy

Statements: A ≥ B > C, D = C, E < D. Conclusions: I. A > E. II. B > E.

  1. A.Only conclusion I follows
  2. B.Only conclusion II follows
  3. C.Both I and II followCorrect
  4. D.Neither I nor II follows

Solution

A ≥ B > C = D > E. So A ≥ B > C = D > E. A > E (I follows). B > C = D > E, so B > E (II follows). Both follow.

2Easy

Statements: P ≤ Q = R, R > S, S ≥ T. Conclusions: I. Q > T. II. P ≤ R.

  1. A.Only conclusion I follows
  2. B.Only conclusion II follows
  3. C.Both I and II followCorrect
  4. D.Neither I nor II follows

Solution

Q = R > S ≥ T, so Q > T (I follows). P ≤ Q = R, so P ≤ R (II follows). Both follow.

3Medium

Statements: G > H ≥ I = J < K ≤ L. Conclusions: I. G > J II. L > I. Which of the following is true?

  1. A.Only conclusion I is true
  2. B.Only conclusion II is true
  3. C.Both conclusions I and II are trueCorrect
  4. D.Neither conclusion I nor II is true

Solution

For conclusion I: G > H ≥ I = J implies G > J. For conclusion II: L ≥ K > J = I implies L > I. Therefore, both conclusions are true.

4mediumAsked in 2021

Statements: A@V&U&B; K#C%B@P Conclusions:

  1. A.A^C
  2. B.V&CCorrect
  3. C.P@U
  4. D.K&P
  5. E.A&P

Solution

Given A>V>=U>=B>=C and P<B, then V>=C is true. Thus, V&C is the correct answer.

5mediumAsked in 2021

Statements: A#C%B^O; Y@S&N^E^O Conclusions:

  1. A.C@N
  2. B.A%S
  3. C.S@O
  4. D.C#E
  5. E.C%SCorrect

Solution

Given A<C<=B=O=E=N<=S, then C<=S is true. Thus, C%S is the correct answer.

6hard

Solve the linear inequality for x: 2x - 5 < 23.

  1. A.x > 14
  2. B.x ≥ 14
  3. C.x ≤ 14
  4. D.x < 16
  5. E.x < 14Correct

Solution

2x - 5 < 23 => 2x < 23 + 5 = 28 => x < 28 / 2 = 14.

7medium

Solve the linear inequality for x: 2x - 7 < 185.

  1. A.x < 96Correct
  2. B.x ≤ 96
  3. C.x > 96
  4. D.x ≥ 96
  5. E.x < 98

Solution

2x - 7 < 185 => 2x < 185 + 7 = 192 => x < 192 / 2 = 96.

8medium

If x @ y means x is not greater than y; x # y means x is not smaller than y. Now assuming the given statements to be true, find which of the following conclusions is definitely true given the statements: Statements: A @ B, B # C Conclusions: I. A @ C II. A # C III. A = C

  1. A.Only I is true
  2. B.Only II is true
  3. C.Only III is true
  4. D.Either I or III is trueCorrect

Solution

Decoding: x @ y means x <= y x # y means x >= y Given: A <= B, B >= C I. A @ C means A <= C. This is not necessarily true. A could be greater than C, equal to C, or less than C. II. A # C means A >= C. This is not necessarily true. A could be greater than C, equal to C, or less than C. III. A = C. This is not necessarily true. A could be greater than C, equal to C, or less than C. However, if B = A and B = C, then A = C. Also, if A <= B and B >= C, it is possible that A <= C. Thus, either A <= C or A = C could be true, but we cannot say for sure. Given that B is between A and C, A <= B >= C. This means it is possible for A <= C, and if A = B and B = C, then A = C. Thus, either I or III could be true.

9hard

For what values of x is x² + 1 > 0?

  1. A.All real numbersCorrect
  2. B.x > 1 or x < -1
  3. C.-1 < x < 1
  4. D.No real numbers

Solution

Since x² is always non-negative (x² ≥ 0), x² + 1 is always greater than 0 for any real number x. Therefore, the solution is all real numbers.

10hard

If A © B means A is greater than B; A £ B means A is either greater than or equal to B; A µ B means A is smaller than B; A ª B means A is either smaller than or equal to B; A ® B means A is equal to B. Now assuming the given statements to be true, which of the following conclusions is definitely true? Statements: M £ N, N ® O, O © P Conclusions: I. M £ O II. P µ N III. M © P

  1. A.Only I is true
  2. B.Only II is true
  3. C.Only III is trueCorrect
  4. D.Only I and III are true

Solution

Decoding: A © B means A > B A £ B means A >= B A µ B means A < B A ª B means A <= B A ® B means A = B Given: M >= N, N = O, O > P I. M £ O means M >= O. Since M >= N and N = O, then M >= O. This is true. II. P µ N means P < N. We have O > P and N = O, then N > P or P < N. So, II is true. III. M © P means M > P. We have M >= N = O > P. So, M > P. Thus, III is true. The question asks for which conclusion is *definitely* true. M >= O is true, but not strictly M > O. P < N is true, but M > P is also true. Since M > P, M >= O and P < N are also true. Since M > P, it implies that M is greater than P, so only III is true.

11medium

Solve the linear inequality for x: 2x - 7 < 133.

  1. A.x < 70Correct
  2. B.x ≥ 70
  3. C.x < 72
  4. D.x > 70
  5. E.x ≤ 70

Solution

2x - 7 < 133 => 2x < 133 + 7 = 140 => x < 140 / 2 = 70.

12hard

Solve the linear inequality for x: 2x - 5 < 31.

  1. A.x ≥ 18
  2. B.x ≤ 18
  3. C.x < 18Correct
  4. D.x < 20
  5. E.x > 18

Solution

2x - 5 < 31 => 2x < 31 + 5 = 36 => x < 36 / 2 = 18.

Inequality — Frequently Asked Questions

What is the key rule for combining inequalities?

A definite relation between two elements needs an unbroken chain of same-direction inequalities between them. If the chain changes direction (A > B < C), the relation between A and C cannot be determined.

How do coded inequalities differ?

Only in translation — first rewrite the coded symbols as standard ones, then solve normally. Writing the decoded chain down eliminates the memory errors the coding is designed to cause.

How many Inequality practice questions does Parikshala have for IBPS PO?

44 exam-pattern Inequality questions for IBPS PO Reasoning Ability, each with a step-by-step solution. Practice is free — no sign-up needed to start.

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Practice Inequality for IBPS PO

44 exam-pattern questions with step-by-step solutions. Start free — no sign-up needed.