What Percentage Questions Test
- Fraction–percentage conversions both ways
- Percentage increase and decrease on a base value
- Successive percentage change (a% then b%)
- Finding the original value after a known change
- Population, income and marks-based word problems
Question bank coverage by sub-pattern
How Percentage Appears in IBPS PO
Percentage is part of the Quantitative Aptitude section (20% of the IBPS PO syllabus). See the full IBPS PO Prelims breakdown.
Percentage Solved Examples for IBPS PO
12 exam-pattern percentage questions from the practice bank, each with a full solution.
If 38% of the all laptops sold by store E are gaming laptops and remaining are non gaming laptops, then find out the number of non gaming laptops sold by store E.
- A.1308
- B.1372
- C.1250
- D.1544
- E.1488Correct
Solution
First find the value of z using the given equation. Then calculate the number of laptops sold by store E. Finally, calculate 62% of that number to find the number of non-gaming laptops.
A number is increased by 20% and then decreased by 20%. What is the net percentage change?
- A.4% decreaseCorrect
- B.4% increase
- C.No change
- D.10% decrease
Solution
Let the number be 100. After increasing by 20%, it becomes 120. After decreasing by 20%, it becomes 120 - (20/100)*120 = 120 - 24 = 96. Therefore, the net change is a decrease of 4%.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
- A.4.37%
- B.5%Correct
- C.6%
- D.8%
Solution
Increase in population = 2,62,500 - 1,75,000 = 87,500. Percentage increase in 10 years = (87,500/1,75,000) * 100 = 50%. Average percent increase per year = 50/10 = 5%.
115. In an examination P attempted 40 questions so far and 30% of them attempted correct. If P attempted remaining Z questions, out of which Y% are correct, so in the exam, number of correct and incorrect questions attempted by him are same. If out of Z questions attempted, 90% are correct so total correct questions attempted by P is (Y + 24). Find total number of questions in the exam. Consider P attempted all questions in the exam.
- A.240
- B.150
- C.120Correct
- D.170
- E.None of these
Solution
Number of correct questions attempted by P so far = 40 × 30/100 = 12. Number of incorrect questions attempted by P so far = 40 – 12 = 28. Number of correct questions attempted by P in remaining Z questions = Y + 24. Number of incorrect questions attempted by P in remaining Z questions = Z – (Y + 24). 12 + Y + 24 = 28 + Z – (Y + 24). 2Y + 36 = Z + 4. Z = 2Y + 32. (Y + 24)/Z = 90/100. 10Y + 240 = 18Y + 288. 8Y = 48. Y = 6. Z = 2 × 6 + 32 = 44. Total number of questions in the exam = 40 + 44 = 84.
The number of candidates applied in company R is what percentage of the number of candidates applied in company P?
- A.75%
- B.50%
- C.60%Correct
- D.80%
- E.None of these
Solution
The number of candidates applied in company R is three fifth of the total number of candidates applied in the company P. 3/5 = 60%.
Directions (107-109): Study the data carefully and answer the following questions: Three boats K, L, and M are traveling some distance in a river, and the speed of the stream of the river is 4 km/h. The speed of the boat L in still water is equal to the speed of the boat K in upstream which is equal to 12 km/h. Boat M travels 35 km in upstream in 2.5 hours and in upstream, Boat L travels 3 km less in upstream than boat M. Boats K and M travel (upstream + downstream) for total 5 hours and 4.5 hours, respectively. Boat L travels 48 km in downstream which is 18 km more than the distance travelled by boat K in downstream 108. The time taken by boat K in upstream is what percentage more or less than the time taken by boat L in upstream?
- A.20% more
- B.33.33% lessCorrect
- C.18.3% more
- D.12.5% less
- E.10% less
Solution
Speed of boat K in upstream = 12 km/h. Speed of boat L in still water = 12 km/h. Speed of boat M in upstream = 35/2.5 = 14 km/h. Speed of boat M in still water = 14 + 4 = 18 km/h. Distance travelled by boat L in upstream = 35 – 3 = 32 km. Speed of boat K in still water = 12 + 4 = 16 km/h. Distance travelled by boat K in downstream = 48 – 18 = 30 km. Speed of boat M in downstream = 18 + 4 = 22 km/h. Distance travelled by boat M in downstream = 22 × 1.5 = 33 km. Required ratio = 32 : 33.
Directions (110-113): Study the following information carefully and answer the questions given below. Some recruitment is done by three companies, i.e., A, B and C. The number of vacancies in company A, B and C are 3, 6 and 1 respectively. The number of candidates, who got interview call per vacancy in company A, company B and company C are 30, 3x and 2x respectively. The total number of candidates applied in company C is one fourth of the total number of candidates applied in company B and three fifth of the total number of candidates applied in company A. The difference between the number of candidates got interview call in company B and C is 160. 111. The number of candidates who applied in company C is what percentage of the number of candidates who applied in company A?
- A.75%
- B.50%
- C.60%Correct
- D.80%
- E.None of these
Solution
Let the number of candidates applied in company A be 20y. Then, the number of candidates applied in company B = 4 × 3y = 12y. Number of candidates applied in company C = 3y. 6 × 3x – 1 × 2x = 160. 16x = 160. x = 10. 3 × 30 = 90. 6 × 3x = 180. 1 × 2x = 20. 3y/20y = 3/5. y = 10. Required number = 12 × 50 = 600.
The price of an article is first increased by 20% and then decreased by 25%. What is the net percentage change in the price?
- A.10% decreaseCorrect
- B.5% decrease
- C.10% increase
- D.5% increase
Solution
Using the formula: x + y + (xy/100), where x = 20 and y = -25. 20 - 25 + (20 * -25)/100 = -5 - 5 = -10. Therefore, the net percentage change is a 10% decrease.
If the price of rice increases by 40%, by what percentage should a household reduce its consumption so that total expenditure remains unchanged? (Case 45)
- A.30%
- B.28.57%Correct
- C.26.5%
- D.33.33%
- E.25%
Solution
Reduction in consumption = [R / (100 + R)] × 100 = [40 / (100 + 40)] × 100 = (40 / 140) × 100 = 28.57%.
If the price of petrol increases by 20% and a person intends to spend only 8% more on petrol, by what percentage should he reduce the quantity of petrol purchased?
- A.10%Correct
- B.12%
- C.8%
- D.15%
Solution
Let the initial price be Rs. 100 and the initial consumption be 100 litres. Initial expenditure = 100 * 100 = Rs. 10000. New price = Rs. 120. New expenditure = 10000 * 1.08 = Rs. 10800. New consumption = 10800/120 = 90 litres. Percentage reduction in consumption = (100 - 90)/100 * 100 = 10%.
Meena spends 35% of his monthly income on food, 20% on house rent, and 10% on children's education. If he saves ₹19,600 per month, find his total monthly income.
- A.₹58,000
- B.₹56,000Correct
- C.₹54,000
- D.₹52,000
- E.₹60,000
Solution
Total expenditure percentage = 35% + 20% + 10% = 65%. Savings percentage = 100% - 65% = 35%. Since 35% of Income = ₹19,600, Monthly Income = (19,600 × 100) / 35 = ₹56,000.
Vikas spends 35% of his monthly income on food, 25% on house rent, and 10% on children's education. If he saves ₹42,000 per month, find his total monthly income.
- A.₹138,000
- B.₹142,000
- C.₹144,000
- D.₹136,000
- E.₹140,000Correct
Solution
Total expenditure percentage = 35% + 25% + 10% = 70%. Savings percentage = 100% - 70% = 30%. Since 30% of Income = ₹42,000, Monthly Income = (42,000 × 100) / 30 = ₹140,000.
Percentage — Frequently Asked Questions
Why do toppers prioritise percentage practice?
Because the concept repeats inside profit & loss, interest and data interpretation questions — mastering it once raises your speed across a third of the quant section.
What should I memorise for percentage questions?
The fraction equivalents of common percentages (1/8 = 12.5%, 1/6 = 16.67%, 1/12 = 8.33%). Converting to fractions turns most exam-pattern percentage questions into one-line calculations.
How many Percentage practice questions does Parikshala have for IBPS PO?
41 exam-pattern Percentage questions for IBPS PO Quantitative Aptitude, each with a step-by-step solution. Practice is free — no sign-up needed to start.