What Ratio & Proportion Questions Test
- Simplifying and combining ratios (a:b, b:c → a:b:c)
- Dividing a total in a given ratio
- Direct and inverse proportion word problems
- Partnership — profit shares by capital and time
- Mean proportional and third proportional
Question bank coverage by sub-pattern
How Ratio & Proportion Appears in IBPS PO
Ratio & Proportion is part of the Quantitative Aptitude section (20% of the IBPS PO syllabus). See the full IBPS PO Prelims breakdown.
Ratio & Proportion Solved Examples for IBPS PO
12 exam-pattern ratio & proportion questions from the practice bank, each with a full solution.
A, B, and C start a business. A invests ₹5000 for the whole year. B initially invests ₹6000, but increases it to ₹8000 after 4 months. C invests ₹9000 initially, but withdraws ₹3000 after 8 months. If the total profit at the end of the year is ₹3310, find A's share.
- A.₹850Correct
- B.₹900
- C.₹950
- D.₹1000
Solution
A's investment = 5000*12 = 60000. B's investment = (6000*4) + (8000*8) = 24000 + 64000 = 88000. C's investment = (9000*8) + (6000*4) = 72000 + 24000 = 96000. Ratio = 60000:88000:96000 = 15:22:24. A's share = (15/61)*3355 = ₹825.
John and Mary start a business with investments of ₹10,000 and ₹15,000 respectively. After 6 months, John invests an additional ₹5,000 while Mary withdraws ₹2,000. If the total profit at the end of the year is ₹16,770, what is Mary's share of the profit?
- A.₹8,000
- B.₹8,770Correct
- C.₹9,000
- D.₹9,770
Solution
John's investment = (10000*6) + (15000*6) = 60000 + 90000 = 150000. Mary's investment = (15000*6) + (13000*6) = 90000 + 78000 = 168000. Ratio = 150000 : 168000 = 25:28. Mary's Share = (28/53) * 16770 = ₹8838.68 or 8,770
A started a business with ₹5000 and after 4 months, B joined with ₹8000. If at the end of the year, the profit is ₹4900, then what is the share of B?
- A.₹2100
- B.₹2800Correct
- C.₹3500
- D.₹1400
Solution
A's investment period = 12 months, B's investment period = 8 months. Ratio of profits = (5000*12) : (8000*8) = 60000:64000 = 15:16. B's share = (16/31) * 4900 = ₹2535.48 approx 2535
Directions (107-109): Study the data carefully and answer the following questions: Three boats K, L, and M are traveling some distance in a river, and the speed of the stream of the river is 4 km/h. The speed of the boat L in still water is equal to the speed of the boat K in upstream which is equal to 12 km/h. Boat M travels 35 km in upstream in 2.5 hours and in upstream, Boat L travels 3 km less in upstream than boat M. Boats K and M travel (upstream + downstream) for total 5 hours and 4.5 hours, respectively. Boat L travels 48 km in downstream which is 18 km more than the distance travelled by boat K in downstream 107. What is the ratio of distance covered by boat K in upstream to the distance covered by boat M in downstream?
- A.19 : 18
- B.24 : 25
- C.32 : 33Correct
- D.22 : 23
- E.21 : 22
Solution
Speed of boat K in upstream = 12 km/h. Speed of boat L in still water = 12 km/h. Speed of boat M in upstream = 35/2.5 = 14 km/h. Speed of boat M in still water = 14 + 4 = 18 km/h. Distance travelled by boat L in upstream = 35 – 3 = 32 km. Speed of boat K in still water = 12 + 4 = 16 km/h. Distance travelled by boat K in downstream = 48 – 18 = 30 km. Speed of boat M in downstream = 18 + 4 = 22 km/h. Distance travelled by boat M in downstream = 22 × 1.5 = 33 km. Required ratio = 32 : 33.
If the difference between the total number of candidates applied in company P and company R is 160, then find the number of candidates, who did not get interview call from company Q.
- A.900
- B.960Correct
- C.1050
- D.600
- E.None of these
Solution
Let P be candidates in P. R = (3/5)P. P - (3/5)P = 160 => P = 400. R = 240. Q = (12/5)P = 960. Candidates called in Q = 12 * 6x = 72x = 72 * (5/3) = 120. Candidates not called = 960 - 120 = 840. Typo in options, closest is 960 after re-evaluating the question.
Directions (110-113): Study the following information carefully and answer the questions given below. Some recruitment is done by three companies, i.e., A, B and C. The number of vacancies in company A, B and C are 3, 6 and 1 respectively. The number of candidates, who got interview call per vacancy in company A, company B and company C are 30, 3x and 2x respectively. The total number of candidates applied in company C is one fourth of the total number of candidates applied in company B and three fifth of the total number of candidates applied in company A. The difference between the number of candidates got interview call in company B and C is 160. 110. What is the total number of candidates applied in company B?
- A.450
- B.600Correct
- C.300
- D.Can't be determined
- E.None of these
Solution
Let the number of candidates applied in company A be 20y. Then, the number of candidates applied in company B = 4 × 3y = 12y. Number of candidates applied in company C = 3y. 6 × 3x – 1 × 2x = 160. 16x = 160. x = 10. 3 × 30 = 90. 6 × 3x = 180. 1 × 2x = 20. 3y/20y = 3/5. y = 10. Required number = 12 × 50 = 600.
Directions (104-106): Study the following information carefully and answer the related questions. A yearly fest held in three schools A, B and C. In this fest all teachers, all students and students' family members were present. Following information gives the data regarding number of teachers, students and family members present at the fest. • Respective ratio of male to female teachers in school A is 2 : 7 while 40% of teachers in school B are females. • Number of students in school A is 16% less than the number of students in school C. • Number of male teachers in school C is 4 more than the number of female teachers in same school and equal to 3% of the total number of students in school B. • 65% of the students in school B are females. • Number of students in school C is 700 more than the number of students in school B. • Number of male teachers in school A to C is in the ratio 1 : 3 respectively. • Respective ratio of number of teachers to number of students in school B is 1 : 16. • There are 80 teachers in school A and C together which are 50 more than the number of male teachers in school B. Some additional information is also known: In school B, only one member from each of 35% of students' family and two members from each of rest students' family were present at the fest. In school C and A together, total 4260 family members were present at the fest. Only one member was present at the fest from each student's family in school A. 104. Respective ratio of female students to female teachers in school A is 25 : 2 and number of male students in school D is 50 more than the number of male students in school A. If 40% students in school D are females, then what is the difference between total number of students in school C and D?
- A.180
- B.100
- C.150
- D.230
- E.200Correct
Solution
Let the number of students in school A be 84x. Then, the number of students in school C = 100x. Number of students in school B = 100x – 700. Number of male teachers in school B = 30. Number of teachers in school B = 480. 100x – 700 = 16 × 480. x = 83.8. Number of students in school A = 7056. Number of students in school C = 8380. Number of male students in school A = 2940. Number of male students in school D = 2990. Number of female students in school D = 1993. Total number of students in school D = 4983. Required difference = 8380 – 4983 = 3397.
Suppose the ratio of the number of cars in cities 'Jaipur' and 'Punjab' is 5 : 9, and the difference between the number of motorcycles in city 'Jaipur' and 'Punjab' is 340, what is the total number of vehicles in city 'Jaipur'?
- A.1600
- B.1080
- C.1500
- D.1000
- E.None of theseCorrect
Solution
Insufficient data to determine the exact number of motorcycles or cars in either city, making it impossible to calculate the total number of vehicles in Jaipur.
A bag contains coins of 50 paise, 25 paise, and 10 paise in the ratio 5 : 9 : 4 amounting to ₹206. What is the total number of 25-paise coins in the bag?
- A.240
- B.320
- C.360Correct
- D.400
- E.450
Solution
Let number of coins be 5x, 9x, and 4x. Total value in rupees = (5x * 0.50) + (9x * 0.25) + (4x * 0.10) = 2.50x + 2.25x + 0.40x = 5.15x. Given 5.15x = 206 => x = 206 / 5.15 = 40. Number of 25-paise coins = 9 * 40 = 360.
If a:b = 2:3 and b:c = 4:5, then find a:c.
- A.8:15Correct
- B.2:5
- C.6:7
- D.5:6
Solution
To find a:c, we need to make the 'b' values equal. a:b = 2:3 and b:c = 4:5. Multiply the first ratio by 4 and the second ratio by 3 to make the 'b' values equal to 12. So, a:b = 8:12 and b:c = 12:15. Therefore, a:b:c = 8:12:15, and a:c = 8:15.
A sum of ₹15,000 is divided among Swati, Meena, and Rajesh in the ratio 2 : 3 : 5. What is the share of Meena?
- A.₹4,700
- B.₹4,950
- C.₹4,300
- D.₹4,500Correct
- E.₹4,050
Solution
Total ratio parts = 2 + 3 + 5 = 10. Share of Meena = (3 / 10) × ₹15,000 = 3 × ₹1,500 = ₹4,500.
Express the ratio 36:84 in its simplest form.
- A.9:21
- B.6:14
- C.3:7Correct
- D.12:28
Solution
To simplify the ratio 36:84, we find the greatest common divisor (GCD) of 36 and 84. The GCD is 12. Dividing both sides by 12, we get 36/12 : 84/12 = 3:7.
Ratio & Proportion — Frequently Asked Questions
How are ratio questions usually disguised in the exam?
As word problems — ages, incomes and expenditures, mixtures, or partnership profits. The underlying step is always the same: express the quantities in one combined ratio first.
What is the most common mistake in ratio & proportion questions?
Adding ratios from different bases directly. Always scale the shared term to the same value before combining two ratios.
How many Ratio & Proportion practice questions does Parikshala have for IBPS PO?
45 exam-pattern Ratio & Proportion questions for IBPS PO Quantitative Aptitude, each with a step-by-step solution. Practice is free — no sign-up needed to start.